56-x+x^2=180

Solution for 56-x+x^2=180 equation:

56-x+x^2=180

We move all terms to the left:

56-x+x^2-(180)=0

We add all the numbers together, and all the variables

x^2-1x-124=0

a = 1; b = -1; c = -124;
Δ = b2-4ac
Δ = -12-4·1·(-124)
Δ = 497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{497}}{2*1}=\frac{1-\sqrt{497}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{497}}{2*1}=\frac{1+\sqrt{497}}{2}
$